UVa 10810: Ultra-QuickSort (Solution)

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Ultra-QuickSort

In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping two adjacent sequence elements until the sequence is sorted in ascending order. For the input sequence

9 1 0 5 4

Ultra-QuickSort produces the output
0 1 4 5 9

Your task is to determine how many swap operations Ultra-QuickSort needs to perform in order to sort a given input sequence.

Input

The input contains several test cases. Every test case begins with a line that contains a single integer n < 50000, the length of the input sequence. Each of the the following n lines contains a single integer 0 ≤ a[i] < 10^10, the i-th input sequence element.

Input is terminated by a sequence of length n = 0. This sequence must not be processed.

The input must be read from standard input.

Output

For every input sequence, your program prints a single line containing the minimum number of swap operations necessary to sort the given input sequence.

The output must be written to standard output.

Sample Input

5
9
1
0
5
4
3
1
2
3
0
Sample Output

6
0

SOLUTION: Python


''' SOLUTION: Python Problem: http://onlinejudge-problems.blogspot.com/2015/09/uva-10810-ultra-quicksort-solution.html '''
from sys import stdin
num,lenn = None,None
def solve (num,low,hi):
cont=0
if low+1<hi:
mid=low+((hi-low)//2)
cont= solve(num,low,mid)
cont+=solve(num,mid,hi)
cont+=(merge(num,low,hi,mid))
return cont
def merge(num,low,hi,mid):
cont=0
i,j=0,0
pparte,sparte=num[low:mid],num[mid:hi]
for k in range(low,hi):
if i==mid-low:
num[k]=sparte[j]
j+=1
elif j==hi-mid:
num[k]=pparte[i]
i+=1
else:
if pparte[i]<=sparte[j]:
num[k]=pparte[i]
i+=1
else:
num[k]=sparte[j]
j+=1
cont+=((mid-low)-i)
return cont
def main():
global num,lenn
inp = stdin
lenn = int(stdin.readline())
while lenn>0:
num = [ int(stdin.readline()) for i in range(lenn) ]
print(solve(num,0,lenn))
lenn = int(stdin.readline())
main()

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